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Battle of Leuze

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Battle of Leuze
Part of the War of the Grand Alliance
Date September 18, 1691
Location Leuze-en-Hainaut, present-day Belgium
Result French victory
Combatants
France England
United Provinces
Commanders
Marshal Luxembourg Friedrich of Waldeck
Strength
28 squadrons 72 squadrons
Casualties
400 dead or wounded 1,500 - 2,000 dead or wounded
War of the Grand Alliance
WalcourtFleurusBeachy HeadStaffardaCuneo – LeuzeBarfleur-La Hogue1st NamurSteenkirkLandenMarsagliaCharleroiTorroella – 2nd NamurBarcelona

The Battle of Leuze took place on September 18, 1691, and was a famous French cavalry victory in the War of the Grand Alliance, against a superior allied force.

Marshal Luxembourg was informed that William III of Orange had left for England in the supposition that the campaign of 1691 was at its end. He was also informed that Waldeck , who was left in charge, was preparing for wintercamp.

Marshal Luxembourg was near Tournai and sent out reconnaissance under Marsilly , that told him that the main body of the allied army was moving away, leaving a rear-guard of cavalry at Leuze.

Luxembourg acted inmediately. He send a detachment to follow the movements of the main body, and with the squadrons of Villars and Marsilly he attacked without warning. The French cavalry charged, only using their swords.

The allied cavalry was superior in numbers, but could not deploy because of the limited space they were manoeuvred into.

The battle lasted for only 2 hours, but was a complete victory for the French. The fleeing rest of the allied cavalry was saved by troops send back by Waldeck.

Luxembourg had been in the tick of the action and had to beat off an attack directed at his person.

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