Cecil, Wisconsin

From Wikipedia, the free encyclopedia

Cecil is a village in Shawano County, Wisconsin, United States. The population was 466 at the 2000 census.

[edit] Geography

Cecil is located at 44°48′34″N, 88°27′8″W (44.809442, -88.452323)^GR1.

According to the United States Census Bureau, the village has a total area of 3.6 km² (1.4 mi²). 3.5 km² (1.4 mi²) of it is land and 0.1 km² (0.04 mi²) of it (2.14%) is water.

[edit] Demographics

As of the census^GR2 of 2000, there were 466 people, 199 households, and 148 families residing in the village. The population density was 131.3/km² (339.0/mi²). There were 246 housing units at an average density of 69.3/km² (179.0/mi²). The racial makeup of the village was 94.85% White, 3.43% Native American, 0.64% Asian, 0.64% from other races, and 0.43% from two or more races. Hispanic or Latino of any race were 0.64% of the population.

There were 199 households out of which 24.6% had children under the age of 18 living with them, 62.8% were married couples living together, 8.5% had a female householder with no husband present, and 25.6% were non-families. 22.6% of all households were made up of individuals and 6.5% had someone living alone who was 65 years of age or older. The average household size was 2.34 and the average family size was 2.70.

Image:Cecil Wisconsin.jpg

In the village the population was spread out with 19.7% under the age of 18, 9.4% from 18 to 24, 24.5% from 25 to 44, 24.2% from 45 to 64, and 22.1% who were 65 years of age or older. The median age was 43 years. For every 100 females there were 96.6 males. For every 100 females age 18 and over, there were 98.9 males.

The median income for a household in the village was $38,958, and the median income for a family was $39,792. Males had a median income of $37,188 versus $23,750 for females. The per capita income for the village was $18,918. About 3.8% of families and 5.7% of the population were below the poverty line, including 10.6% of those under age 18 and 3.5% of those age 65 or over.