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Mertens function

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In number theory, the Mertens function is

<math>M(n) = \sum_{1\le k \le n} \mu(k)</math>

where μ(k) is the Möbius function. The function is named in honour of Franz Mertens.

Because the Möbius function has only the return values -1, 0 and +1, it's obvious that the Mertens function moves slowly and that there is no x such that M(x) > x. The Mertens conjecture goes even further, stating that there is no x where the absolute value of the Mertens function exceeds the square root of x. The Mertens conjecture was disproven in 1985. However, the Riemann hypothesis is equivalent to a weaker conjecture on the growth of M(x), namely <math>M(x) = o(x^{\frac12 + \epsilon})</math>. Since high values for M grow at least as fast as the square root of x, this puts a rather tight bound on its rate of growth. Here, <math>o</math> refers to little-o notation.

[edit] Integral representations

Using the Euler product one finds that

<math> \frac{1}{\zeta(s) }= \prod_{p} (1-p^{-s})= \sum_{n=1}^{\infty}\mu (n)n^{-s} </math>

where <math>\zeta(s)</math> is the Riemann zeta function and the product is taken over primes. Then, using this Dirichlet series with Perron's formula, one obtains:

<math> \frac{1}{2\pi i}\oint_{C}ds \frac{x^{s}}{s\zeta(s) }=M(x) </math>

where "C" is a closed curve encircling all of the roots of <math>\zeta(s).</math>

Conversely, one has the Mellin transform

<math>\frac{1}{\zeta(s)} = s\int_1^\infty \frac{M(x)}{x^{s+1}}\,dx</math>

which holds for <math>Re(s)>1</math>.

A good evaluation, at least asymptotically, would be to obtain, by the method of steepest descent, an inequality:

<math> \oint_{C}dsF(s)e^{st} \sim M(e^{t}) </math>

assuming that there are not multiple non-trivial roots of <math> \zeta (\rho) </math> you have the "exact formula" by residue theorem:

<math> \frac{1}{2 \pi i} \oint _ {C}ds \frac{x^s}{s \zeta (s)} = \sum _ {\rho} \frac{x^{\rho}}{\rho \zeta '(\rho)}-2+\sum_{n=1}^{\infty} \frac{ (-1)^{n-1} (2\pi )^{2n}}{(2n)! n \zeta(2n+1)x^{2n}} </math>

[edit] Calculation

The Mertens function has been computed for an increasing range of n.

Person Year Limit
Mertens 1897 104
von Sterneck 1897 1.5 x 105
von Sterneck 1901 5 x 105
von Sterneck 1912 5 x 106
Neubauer 1963 108
Cohen and Dress 1979 7.8 x 109
Dress 1993 1012
Lioen and van der Lune 1994 1013
Kotnik and van der Lune 2003 1014

[edit] References

es:Función de Mertens fr:Fonction de Mertens ko:메르텐스 함수 it:Funzione di Mertens hu:Mertens-függvény nl:Mertensfunctie pl:Funkcja Mertensa pt:Função de Mertens sl:Mertensova funkcija sv:Mertensfunktionen

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