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Pigeonhole principle

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The inspiration for the name of the principle: pigeons in holes. Here n = 7 and m = 9.

The pigeonhole principle, also known as Dirichlet's box (or drawer) principle, states that if n pigeons are put into m pigeonholes, and n > m, then at least one pigeonhole must contain more than one pigeon. Another way of stating this would be that m holes can hold at most m objects with one object to a hole; adding another object will force you to reuse one of the holes. More formally, the theorem states that there does not exist an injective function on finite sets whose codomain is smaller than its domain.

The pigeonhole principle is an example of a counting argument which can be applied to many formal problems, including ones involving infinite sets that cannot be put into one-to-one correspondence. In Diophantine approximation the quantitative application of the principle to the existence of integer solutions of a system of linear equations goes under the name of Siegel's lemma.

The first statement of the principle is believed to have been made by Dirichlet in 1834 under the name Schubfachprinzip ("drawer principle"). In some languages (for example, Russian) this principle is therefore called the Dirichlet principle (not to be confused with the minimum principle for harmonic functions of the same name); in Italian the original name "principio dei cassetti" is still in use.

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[edit] Examples

An easy example of the pigeonhole principle involves the situation when there are five people who want to play softball, but only four teams. This would not be a problem except that each of the five refuses to play on a team with any of the other 4. To prove that there is no way for all five people to play softball, the pigeonhole principle says that it is impossible to divide five people among four teams without putting two of the people on the same team. Since they refuse to play on the same team, at most four of the people will be able to play.

Although the pigeonhole principle may seem to be a trivial observation, it can be used to demonstrate possibly unexpected results. For example, there must be at least two people in London with the same number of hairs on their heads. Demonstration: a typical head of hair has around 150,000 hairs. It is reasonable to assume that no one has more than 1,000,000 hairs on their head. There are more than 1,000,000 people in London. If we assign a pigeonhole for each number of hairs on a head, and assign people to the pigeonhole with their number of hairs on it, there must be at least two people with the same number of hairs on their heads.


The pigeonhole principle often arises in computer science. For example, collisions are inevitable in a hash table because the number of possible keys exceeds the number of indices in the array. No hashing algorithm, no matter how clever, can avoid these collisions. This principle also proves that there cannot be a lossless compression algorithm that will compress any file by a certain amount. If it could then two files would be compressed to the same smaller file and restoring them would be ambiguous.

Several additional examples are given by Grimaldi (see References).

[edit] Generalizations of the pigeonhole principle

A generalized version of this principle states that, if n discrete objects are to be allocated to m containers, then at least one container must hold no fewer than <math>\lceil n/m \rceil</math> objects, where <math>\lceil x\rceil</math> is the ceiling function, denoting the smallest integer larger than or equal to x.

A probabilistic generalization of the pigeonhole principle states that if n pigeons are randomly put into m pigeonholes with uniform probability 1/m, then at least one pigeonhole will hold more than one pigeon with probability

<math>1 - \frac{m!}{(m-n)!\;m^n} = 1 - \frac{(m)_n}{m^n}, \!</math>

where (m)n is a falling factorial. For n = 0 and for n = 1 (and m > 0), that probability is zero; in other words, if there is just one pigeon, there cannot be a conflict. For n > m (more pigeons than pigeonholes) it is one, in which case it coincides with the ordinary pigeonhole principle. But even if the number of pigeons does not exceed the number of pigeonholes (nm), due to the random nature of the assignment of pigeons to pigeonholes there is often a substantial chance that clashes will occur. For example, if 2 pigeons are randomly assigned to 4 pigeonholes, there is a 25% chance that at least one pigeonhole will hold more than one pigeon; for 5 pigeons and 10 holes, that probability is 69.76%; and for 10 pigeons and 20 holes it is about 93.45%. This problem is treated at much greater length at birthday paradox.

[edit] Application examples

  • If there are n persons who can arbitrarily shake hands with one another, there is always a pair of persons who shake the same number of hands: one can shake 0 to n − 1 number of hands. Suppose all of the n persons shake hands at least once, so as every person in will shake from 1 to n − 1 hands. There are n persons and just n − 1 hands shaken. Thus, because of pigeonhole, there must be two people shaking the same number of hands.

[edit] References

[edit] See also

[edit] External links

de:Schubfachprinzip es:Principio del palomar fr:Principe des tiroirs ko:비둘기집 원리 is:Skúffuregla Dirichlets it:Principio dei cassetti he:עקרון שובך היונים nl:Duiventilprincipe ja:鳩の巣原理 pl:Zasada szufladkowa Dirichleta pt:Princípio da Casa dos Pombos ru:Принцип Дирихле fi:Kyyhkyslakkaperiaate sv:Dirichlets lådprincip zh:鴿巢原理

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